(2x-3)(2x-1)+4=0

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Solution for (2x-3)(2x-1)+4=0 equation: 



(2x-3)(2x-1)+4=0

We multiply parentheses ..

(+4x^2-2x-6x+3)+4=0

We get rid of parentheses

4x^2-2x-6x+3+4=0

We add all the numbers together, and all the variables

4x^2-8x+7=0

a = 4; b = -8; c = +7;
Δ = b2-4ac
Δ = -82-4·4·7
Δ = -48
Delta is less than zero, so there is no solution for the equation

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