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(2x-3)(2x-3)-(7+3x)(3x-7)=12-43x-(4-x)(1-5x)
We move all terms to the left:
(2x-3)(2x-3)-(7+3x)(3x-7)-(12-43x-(4-x)(1-5x))=0
We add all the numbers together, and all the variables
(2x-3)(2x-3)-(3x+7)(3x-7)-(12-43x-(-1x+4)(-5x+1))=0
We use the square of the difference formula
9x^2+(2x-3)(2x-3)-(12-43x-(-1x+4)(-5x+1))+49=0
We multiply parentheses ..
9x^2+(+4x^2-6x-6x+9)-(12-43x-(-1x+4)(-5x+1))+49=0
We calculate terms in parentheses: -(12-43x-(-1x+4)(-5x+1)), so:We get rid of parentheses
12-43x-(-1x+4)(-5x+1)
determiningTheFunctionDomain -43x-(-1x+4)(-5x+1)+12
We multiply parentheses ..
-(+5x^2-1x-20x+4)-43x+12
We get rid of parentheses
-5x^2+1x+20x-43x-4+12
We add all the numbers together, and all the variables
-5x^2-22x+8
Back to the equation:
-(-5x^2-22x+8)
9x^2+4x^2+5x^2-6x-6x+22x+9-8+49=0
We add all the numbers together, and all the variables
18x^2+10x+50=0
a = 18; b = 10; c = +50;
Δ = b2-4ac
Δ = 102-4·18·50
Δ = -3500
Delta is less than zero, so there is no solution for the equation
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