(2x-3)(2x-3)=3x(x-4)

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Solution for (2x-3)(2x-3)=3x(x-4) equation: 



(2x-3)(2x-3)=3x(x-4)

We move all terms to the left:

(2x-3)(2x-3)-(3x(x-4))=0

We multiply parentheses ..

(+4x^2-6x-6x+9)-(3x(x-4))=0



We calculate terms in parentheses: -(3x(x-4)), so:

3x(x-4)

We multiply parentheses

3x^2-12x

Back to the equation:

-(3x^2-12x)



We get rid of parentheses

4x^2-3x^2-6x-6x+12x+9=0

We add all the numbers together, and all the variables

x^2+9=0

a = 1; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·1·9
Δ = -36
Delta is less than zero, so there is no solution for the equation

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