(2x-3)(3x+1)=(3x-1)(2x-1)

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Solution for (2x-3)(3x+1)=(3x-1)(2x-1) equation: 



(2x-3)(3x+1)=(3x-1)(2x-1)

We move all terms to the left:

(2x-3)(3x+1)-((3x-1)(2x-1))=0

We multiply parentheses ..

(+6x^2+2x-9x-3)-((3x-1)(2x-1))=0



We calculate terms in parentheses: -((3x-1)(2x-1)), so:

(3x-1)(2x-1)

We multiply parentheses ..

(+6x^2-3x-2x+1)

We get rid of parentheses

6x^2-3x-2x+1

We add all the numbers together, and all the variables

6x^2-5x+1

Back to the equation:

-(6x^2-5x+1)



We get rid of parentheses

6x^2-6x^2+2x-9x+5x-3-1=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2

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