(2x-3)(3x+2)=(x+1)(x+1)+(5x+2)(x-14)

Solution for (2x-3)(3x+2)=(x+1)(x+1)+(5x+2)(x-14) equation:

(2x-3)(3x+2)=(x+1)(x+1)+(5x+2)(x-14)

We move all terms to the left:

(2x-3)(3x+2)-((x+1)(x+1)+(5x+2)(x-14))=0

We multiply parentheses ..

(+6x^2+4x-9x-6)-((x+1)(x+1)+(5x+2)(x-14))=0


We calculate terms in parentheses: -((x+1)(x+1)+(5x+2)(x-14)), so:

(x+1)(x+1)+(5x+2)(x-14)

We multiply parentheses ..

(+x^2+x+x+1)+(5x+2)(x-14)

We get rid of parentheses

x^2+x+x+(5x+2)(x-14)+1

We multiply parentheses ..

x^2+(+5x^2-70x+2x-28)+x+x+1

We add all the numbers together, and all the variables

x^2+(+5x^2-70x+2x-28)+2x+1

We get rid of parentheses

x^2+5x^2-70x+2x+2x-28+1

We add all the numbers together, and all the variables

6x^2-66x-27

Back to the equation:

-(6x^2-66x-27)


We get rid of parentheses

6x^2-6x^2+4x-9x+66x-6+27=0

We add all the numbers together, and all the variables

61x+21=0

We move all terms containing x to the left, all other terms to the right

61x=-21

x=-21/61

x=-21/61