(2x-3)(3x+5)=6x2

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Solution for (2x-3)(3x+5)=6x2 equation: 



(2x-3)(3x+5)=6x^2

We move all terms to the left:

(2x-3)(3x+5)-(6x^2)=0

determiningTheFunctionDomain
-6x^2+(2x-3)(3x+5)=0

We multiply parentheses ..

-6x^2+(+6x^2+10x-9x-15)=0

We get rid of parentheses

-6x^2+6x^2+10x-9x-15=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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