(2x-3)(3x-5)=(6x-5)(x-1)

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Solution for (2x-3)(3x-5)=(6x-5)(x-1) equation: 



(2x-3)(3x-5)=(6x-5)(x-1)

We move all terms to the left:

(2x-3)(3x-5)-((6x-5)(x-1))=0

We multiply parentheses ..

(+6x^2-10x-9x+15)-((6x-5)(x-1))=0



We calculate terms in parentheses: -((6x-5)(x-1)), so:

(6x-5)(x-1)

We multiply parentheses ..

(+6x^2-6x-5x+5)

We get rid of parentheses

6x^2-6x-5x+5

We add all the numbers together, and all the variables

6x^2-11x+5

Back to the equation:

-(6x^2-11x+5)



We get rid of parentheses

6x^2-6x^2-10x-9x+11x+15-5=0

We add all the numbers together, and all the variables

-8x+10=0

We move all terms containing x to the left, all other terms to the right

-8x=-10

x=-10/-8

x=1+1/4

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