(2x-3)(4x+12)=(x-9)(8x+2)

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Solution for (2x-3)(4x+12)=(x-9)(8x+2) equation: 



(2x-3)(4x+12)=(x-9)(8x+2)

We move all terms to the left:

(2x-3)(4x+12)-((x-9)(8x+2))=0

We multiply parentheses ..

(+8x^2+24x-12x-36)-((x-9)(8x+2))=0



We calculate terms in parentheses: -((x-9)(8x+2)), so:

(x-9)(8x+2)

We multiply parentheses ..

(+8x^2+2x-72x-18)

We get rid of parentheses

8x^2+2x-72x-18

We add all the numbers together, and all the variables

8x^2-70x-18

Back to the equation:

-(8x^2-70x-18)



We get rid of parentheses

8x^2-8x^2+24x-12x+70x-36+18=0

We add all the numbers together, and all the variables

82x-18=0

We move all terms containing x to the left, all other terms to the right

82x=18

x=18/82

x=9/41

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