(2x-3)(5x-10)=0

Solution for (2x-3)(5x-10)=0 equation:

(2x-3)(5x-10)=0

We multiply parentheses ..

(+10x^2-20x-15x+30)=0

We get rid of parentheses

10x^2-20x-15x+30=0

We add all the numbers together, and all the variables

10x^2-35x+30=0

a = 10; b = -35; c = +30;
Δ = b2-4ac
Δ = -352-4·10·30
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-5}{2*10}=\frac{30}{20}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+5}{2*10}=\frac{40}{20}
=2
$