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(2x-3)(7x-2)=0
We multiply parentheses ..
(+14x^2-4x-21x+6)=0
We get rid of parentheses
14x^2-4x-21x+6=0
We add all the numbers together, and all the variables
14x^2-25x+6=0
a = 14; b = -25; c = +6;
Δ = b2-4ac
Δ = -252-4·14·6
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-17}{2*14}=\frac{8}{28} =2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+17}{2*14}=\frac{42}{28} =1+1/2 $
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