(2x-3)(x+1)=2x2-3x+4

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Solution for (2x-3)(x+1)=2x2-3x+4 equation: 



(2x-3)(x+1)=2x^2-3x+4

We move all terms to the left:

(2x-3)(x+1)-(2x^2-3x+4)=0

We get rid of parentheses

-2x^2+(2x-3)(x+1)+3x-4=0

We multiply parentheses ..

-2x^2+(+2x^2+2x-3x-3)+3x-4=0

We get rid of parentheses

-2x^2+2x^2+2x-3x+3x-3-4=0

We add all the numbers together, and all the variables

2x-7=0

We move all terms containing x to the left, all other terms to the right

2x=7

x=7/2

x=3+1/2

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