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(2x-3)(x+2)-(x+4)(x-3)+5=0
We multiply parentheses ..
(+2x^2+4x-3x-6)-(x+4)(x-3)+5=0
We get rid of parentheses
2x^2+4x-3x-(x+4)(x-3)-6+5=0
We multiply parentheses ..
2x^2-(+x^2-3x+4x-12)+4x-3x-6+5=0
We add all the numbers together, and all the variables
2x^2-(+x^2-3x+4x-12)+x-1=0
We get rid of parentheses
2x^2-x^2+3x-4x+x+12-1=0
We add all the numbers together, and all the variables
x^2+11=0
a = 1; b = 0; c = +11;
Δ = b2-4ac
Δ = 02-4·1·11
Δ = -44
Delta is less than zero, so there is no solution for the equation
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