(2x-3)(x+2)=3(x-2

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Solution for (2x-3)(x+2)=3(x-2 equation: 



(2x-3)(x+2)=3(x-2

We move all terms to the left:

(2x-3)(x+2)-(3(x-2)=0

We multiply parentheses ..

(+2x^2+4x-3x-6)-(3(x-2)=0



We calculate terms in parentheses: -(3(x-2), so:

3(x-2



We get rid of parentheses

2x^2+4x-3x-(3(x-2)-6=0

We add all the numbers together, and all the variables

2x^2+x-(3(x-2)-6=0

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