(2x-3)(x+5)=(x-4)(2x-1)

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Solution for (2x-3)(x+5)=(x-4)(2x-1) equation:



(2x-3)(x+5)=(x-4)(2x-1)
We move all terms to the left:
(2x-3)(x+5)-((x-4)(2x-1))=0
We multiply parentheses ..
(+2x^2+10x-3x-15)-((x-4)(2x-1))=0
We calculate terms in parentheses: -((x-4)(2x-1)), so:
(x-4)(2x-1)
We multiply parentheses ..
(+2x^2-1x-8x+4)
We get rid of parentheses
2x^2-1x-8x+4
We add all the numbers together, and all the variables
2x^2-9x+4
Back to the equation:
-(2x^2-9x+4)
We get rid of parentheses
2x^2-2x^2+10x-3x+9x-15-4=0
We add all the numbers together, and all the variables
16x-19=0
We move all terms containing x to the left, all other terms to the right
16x=19
x=19/16
x=1+3/16

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