(2x-3)(x-6)=2x(x-6)+3x-8

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Solution for (2x-3)(x-6)=2x(x-6)+3x-8 equation: 



(2x-3)(x-6)=2x(x-6)+3x-8

We move all terms to the left:

(2x-3)(x-6)-(2x(x-6)+3x-8)=0

We multiply parentheses ..

(+2x^2-12x-3x+18)-(2x(x-6)+3x-8)=0



We calculate terms in parentheses: -(2x(x-6)+3x-8), so:

2x(x-6)+3x-8

We add all the numbers together, and all the variables

3x+2x(x-6)-8

We multiply parentheses

2x^2+3x-12x-8

We add all the numbers together, and all the variables

2x^2-9x-8

Back to the equation:

-(2x^2-9x-8)



We get rid of parentheses

2x^2-2x^2-12x-3x+9x+18+8=0

We add all the numbers together, and all the variables

-6x+26=0

We move all terms containing x to the left, all other terms to the right

-6x=-26

x=-26/-6

x=4+1/3

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