(2x-3)+(2x+15)=(7x-18)

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Solution for (2x-3)+(2x+15)=(7x-18) equation: 



(2x-3)+(2x+15)=(7x-18)

We move all terms to the left:

(2x-3)+(2x+15)-((7x-18))=0

We get rid of parentheses

2x+2x-((7x-18))-3+15=0



We calculate terms in parentheses: -((7x-18)), so:

(7x-18)

We get rid of parentheses

7x-18

Back to the equation:

-(7x-18)



We add all the numbers together, and all the variables

4x-(7x-18)+12=0

We get rid of parentheses

4x-7x+18+12=0

We add all the numbers together, and all the variables

-3x+30=0

We move all terms containing x to the left, all other terms to the right

-3x=-30

x=-30/-3

x=+10

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