(2x-3)+(3x-1)+(x-5)=87

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Solution for (2x-3)+(3x-1)+(x-5)=87 equation: 



(2x-3)+(3x-1)+(x-5)=87

We move all terms to the left:

(2x-3)+(3x-1)+(x-5)-(87)=0

We get rid of parentheses

2x+3x+x-3-1-5-87=0

We add all the numbers together, and all the variables

6x-96=0

We move all terms containing x to the left, all other terms to the right

6x=96

x=96/6

x=16

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