(2x-3)+(3x-4)+(X+1)=x+x+x+x+8

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Solution for (2x-3)+(3x-4)+(X+1)=x+x+x+x+8 equation: 



(2x-3)+(3x-4)+(x+1)=x+x+x+x+8

We move all terms to the left:

(2x-3)+(3x-4)+(x+1)-(x+x+x+x+8)=0

We add all the numbers together, and all the variables

(2x-3)+(3x-4)+(x+1)-(4x+8)=0

We get rid of parentheses

2x+3x+x-4x-3-4+1-8=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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