(2x-3)+(x+11)=65

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Solution for (2x-3)+(x+11)=65 equation: 



(2x-3)+(x+11)=65

We move all terms to the left:

(2x-3)+(x+11)-(65)=0

We get rid of parentheses

2x+x-3+11-65=0

We add all the numbers together, and all the variables

3x-57=0

We move all terms containing x to the left, all other terms to the right

3x=57

x=57/3

x=19

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