(2x-3)+(x-12)+(7x+1)=

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Solution for (2x-3)+(x-12)+(7x+1)= equation:


Simplifying
(2x + -3) + (x + -12) + (7x + 1) = 0

Reorder the terms:
(-3 + 2x) + (x + -12) + (7x + 1) = 0

Remove parenthesis around (-3 + 2x)
-3 + 2x + (x + -12) + (7x + 1) = 0

Reorder the terms:
-3 + 2x + (-12 + x) + (7x + 1) = 0

Remove parenthesis around (-12 + x)
-3 + 2x + -12 + x + (7x + 1) = 0

Reorder the terms:
-3 + 2x + -12 + x + (1 + 7x) = 0

Remove parenthesis around (1 + 7x)
-3 + 2x + -12 + x + 1 + 7x = 0

Reorder the terms:
-3 + -12 + 1 + 2x + x + 7x = 0

Combine like terms: -3 + -12 = -15
-15 + 1 + 2x + x + 7x = 0

Combine like terms: -15 + 1 = -14
-14 + 2x + x + 7x = 0

Combine like terms: 2x + x = 3x
-14 + 3x + 7x = 0

Combine like terms: 3x + 7x = 10x
-14 + 10x = 0

Solving
-14 + 10x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 10x = 0 + 14

Combine like terms: -14 + 14 = 0
0 + 10x = 0 + 14
10x = 0 + 14

Combine like terms: 0 + 14 = 14
10x = 14

Divide each side by '10'.
x = 1.4

Simplifying
x = 1.4

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