(2x-3)+2(2x-3+6)=32

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Solution for (2x-3)+2(2x-3+6)=32 equation: 



(2x-3)+2(2x-3+6)=32

We move all terms to the left:

(2x-3)+2(2x-3+6)-(32)=0

We add all the numbers together, and all the variables

(2x-3)+2(2x+3)-32=0

We multiply parentheses

(2x-3)+4x+6-32=0

We get rid of parentheses

2x+4x-3+6-32=0

We add all the numbers together, and all the variables

6x-29=0

We move all terms containing x to the left, all other terms to the right

6x=29

x=29/6

x=4+5/6

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