(2x-3)-(5x-2)=(7x+11)

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Solution for (2x-3)-(5x-2)=(7x+11) equation: 



(2x-3)-(5x-2)=(7x+11)

We move all terms to the left:

(2x-3)-(5x-2)-((7x+11))=0

We get rid of parentheses

2x-5x-((7x+11))-3+2=0



We calculate terms in parentheses: -((7x+11)), so:

(7x+11)

We get rid of parentheses

7x+11

Back to the equation:

-(7x+11)



We add all the numbers together, and all the variables

-3x-(7x+11)-1=0

We get rid of parentheses

-3x-7x-11-1=0

We add all the numbers together, and all the variables

-10x-12=0

We move all terms containing x to the left, all other terms to the right

-10x=12

x=12/-10

x=-1+1/5

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