(2x-3)/(2)=(3x+8)/(4)

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Solution for (2x-3)/(2)=(3x+8)/(4) equation: 



(2x-3)/(2)=(3x+8)/(4)

We move all terms to the left:

(2x-3)/(2)-((3x+8)/(4))=0

We calculate fractions


2x/()+(-((3x+8)*2)/()=0



We calculate terms in parentheses: +(-((3x+8)*2)/(), so:

-((3x+8)*2)/(

We multiply all the terms by the denominator


-((3x+8)*2)



We calculate terms in parentheses: -((3x+8)*2), so:

(3x+8)*2

We multiply parentheses

6x+16

Back to the equation:

-(6x+16)



We get rid of parentheses

-6x-16

Back to the equation:

+(-6x-16)



We get rid of parentheses

2x/()-6x-16=0

We multiply all the terms by the denominator


2x-6x*()-16*()=0

We add all the numbers together, and all the variables

2x-6x*()=0

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