(2x-3)/(3)=(1-2x)/(5)

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Solution for (2x-3)/(3)=(1-2x)/(5) equation: 



(2x-3)/(3)=(1-2x)/(5)

We move all terms to the left:

(2x-3)/(3)-((1-2x)/(5))=0

We add all the numbers together, and all the variables

(2x-3)/3-((-2x+1)/5)=0

We calculate fractions


2x/()+(-((-2x+1)*3)/()=0



We calculate terms in parentheses: +(-((-2x+1)*3)/(), so:

-((-2x+1)*3)/(

We multiply all the terms by the denominator


-((-2x+1)*3)



We calculate terms in parentheses: -((-2x+1)*3), so:

(-2x+1)*3

We multiply parentheses

-6x+3

Back to the equation:

-(-6x+3)



We get rid of parentheses

6x-3

Back to the equation:

+(6x-3)



We get rid of parentheses

2x/()+6x-3=0

We multiply all the terms by the denominator


2x+6x*()-3*()=0

We add all the numbers together, and all the variables

2x+6x*()=0

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