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(2x-3)/(3x+1)=1
We move all terms to the left:
(2x-3)/(3x+1)-(1)=0
Domain of the equation: (3x+1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
3x!=-1
x!=-1/3
x!=-1/3
x∈R
(2x-3)-1*(3x+1)=0
We get rid of parentheses
2x-1*(3x+1)-3=0
We move all terms containing x to the left, all other terms to the right
2x-1*(3x+1)=3
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