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(2x-3)/(5x+7)=0
Domain of the equation: (5x+7)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5x!=-7
x!=-7/5
x!=-1+2/5
x∈R
(2x-3)=0
We get rid of parentheses
2x-3=0
We move all terms containing x to the left, all other terms to the right
2x=3
x=3/2
x=1+1/2
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