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(2x-3)/(7x+4)=2/5
We move all terms to the left:
(2x-3)/(7x+4)-(2/5)=0
Domain of the equation: (7x+4)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
7x!=-4
x!=-4/7
x!=-4/7
x∈R
(2x-3)/(7x+4)-(+2/5)=0
We get rid of parentheses
(2x-3)/(7x+4)-2/5=0
We calculate fractions
(10x-15)/(35x+20)+(-14x-8)/(35x+20)=0
We multiply all the terms by the denominator
(10x-15)+(-14x-8)=0
We get rid of parentheses
10x-14x-15-8=0
We add all the numbers together, and all the variables
-4x-23=0
We move all terms containing x to the left, all other terms to the right
-4x=23
x=23/-4
x=-5+3/4
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