(2x-3)/2+5x/(x+1)=x

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Solution for (2x-3)/2+5x/(x+1)=x equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(2*x-3)/2+(5*x)/(x+1) = x // - x

(2*x-3)/2+(5*x)/(x+1)-x = 0

((2*x-3)*(x+1))/(2*(x+1))+(2*5*x)/(2*(x+1))+(2*(-x)*(x+1))/(2*(x+1)) = 0

(2*x-3)*(x+1)+2*(-x)*(x+1)+2*5*x = 0

2*x^2-2*x^2+9*x-2*x-3 = 0

7*x-3 = 0

(7*x-3)/(2*(x+1)) = 0

(7*x-3)/(2*(x+1)) = 0 // * 2*(x+1)

7*x-3 = 0

7*x-3 = 0 // + 3

7*x = 3 // : 7

x = 3/7

x = 3/7

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