(2x-3)/2-(x-3)/4=(3x+1)/4-1

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Solution for (2x-3)/2-(x-3)/4=(3x+1)/4-1 equation: 



(2x-3)/2-(x-3)/4=(3x+1)/4-1

We move all terms to the left:

(2x-3)/2-(x-3)/4-((3x+1)/4-1)=0

We calculate fractions


((2x-3)*4*4)/()+(-2x+6)/()+(-((3x+1)*2)/()=0



We calculate terms in parentheses: +((2x-3)*4*4)/(), so:

(2x-3)*4*4)/(

We multiply all the terms by the denominator


(2x-3)*4*4)

We get rid of parentheses

2x-3)*4*4

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-((3x+1)*2)/(), so:

-((3x+1)*2)/(

We multiply all the terms by the denominator


-((3x+1)*2)



We calculate terms in parentheses: -((3x+1)*2), so:

(3x+1)*2

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

-6x-2

Back to the equation:

+(-6x-2)



We get rid of parentheses

2x+(-2x+6)/()-6x-2=0

We multiply all the terms by the denominator


2x*()+(-2x+6)-6x*()-2*()=0

We add all the numbers together, and all the variables

2x*()+(-2x+6)-6x*()=0

We get rid of parentheses

2x*()-2x-6x*()+6=0

We add all the numbers together, and all the variables

-2x+2x*()-6x*()+6=0

We move all terms containing x to the left, all other terms to the right

-2x+2x*()-6x*()=-6

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