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(2x-3)/3=x-3
We move all terms to the left:
(2x-3)/3-(x-3)=0
We get rid of parentheses
(2x-3)/3-x+3=0
We multiply all the terms by the denominator
(2x-3)-x*3+3*3=0
We add all the numbers together, and all the variables
(2x-3)-x*3+9=0
Wy multiply elements
(2x-3)-3x+9=0
We get rid of parentheses
2x-3x-3+9=0
We add all the numbers together, and all the variables
-1x+6=0
We move all terms containing x to the left, all other terms to the right
-x=-6
x=-6/-1
x=+6
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