(2x-3)/4=(3x-5)/2

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Solution for (2x-3)/4=(3x-5)/2 equation: 



(2x-3)/4=(3x-5)/2

We move all terms to the left:

(2x-3)/4-((3x-5)/2)=0

We calculate fractions


2x/()+(-((3x-5)*4)/()=0



We calculate terms in parentheses: +(-((3x-5)*4)/(), so:

-((3x-5)*4)/(

We multiply all the terms by the denominator


-((3x-5)*4)



We calculate terms in parentheses: -((3x-5)*4), so:

(3x-5)*4

We multiply parentheses

12x-20

Back to the equation:

-(12x-20)



We get rid of parentheses

-12x+20

Back to the equation:

+(-12x+20)



We get rid of parentheses

2x/()-12x+20=0

We multiply all the terms by the denominator


2x-12x*()+20*()=0

We add all the numbers together, and all the variables

2x-12x*()=0

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