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(2x-3)/4=(3x-5)/2
We move all terms to the left:
(2x-3)/4-((3x-5)/2)=0
We calculate fractions
2x/()+(-((3x-5)*4)/()=0
We calculate terms in parentheses: +(-((3x-5)*4)/(), so:We get rid of parentheses
-((3x-5)*4)/(
We multiply all the terms by the denominator
-((3x-5)*4)
We calculate terms in parentheses: -((3x-5)*4), so:We get rid of parentheses
(3x-5)*4
We multiply parentheses
12x-20
Back to the equation:
-(12x-20)
-12x+20
Back to the equation:
+(-12x+20)
2x/()-12x+20=0
We multiply all the terms by the denominator
2x-12x*()+20*()=0
We add all the numbers together, and all the variables
2x-12x*()=0
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