(2x-3)/4=(5-x)/3

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Solution for (2x-3)/4=(5-x)/3 equation:



(2x-3)/4=(5-x)/3
We move all terms to the left:
(2x-3)/4-((5-x)/3)=0
We add all the numbers together, and all the variables
(2x-3)/4-((-1x+5)/3)=0
We calculate fractions
2x/()+(-((-1x+5)*4)/()=0
We calculate terms in parentheses: +(-((-1x+5)*4)/(), so:
-((-1x+5)*4)/(
We multiply all the terms by the denominator
-((-1x+5)*4)
We calculate terms in parentheses: -((-1x+5)*4), so:
(-1x+5)*4
We multiply parentheses
-4x+20
Back to the equation:
-(-4x+20)
We get rid of parentheses
4x-20
Back to the equation:
+(4x-20)
We get rid of parentheses
2x/()+4x-20=0
We multiply all the terms by the denominator
2x+4x*()-20*()=0
We add all the numbers together, and all the variables
2x+4x*()=0

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