(2x-3)/5x=11/2

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Solution for (2x-3)/5x=11/2 equation:


x in (-oo:+oo)

x*((2*x-3)/5) = 11/2 // - 11/2

x*((2*x-3)/5)-(11/2) = 0

x*((2*x-3)/5)-11/2 = 0

(x*(2*x-3))/5-11/2 = 0

(2*x*(2*x-3))/(2*5)+(-11*5)/(2*5) = 0

2*x*(2*x-3)-11*5 = 0

4*x^2-6*x-55 = 0

4*x^2-6*x-55 = 0

4*x^2-6*x-55 = 0

DELTA = (-6)^2-(-55*4*4)

DELTA = 916

DELTA > 0

x = (916^(1/2)+6)/(2*4) or x = (6-916^(1/2))/(2*4)

x = (2*229^(1/2)+6)/8 or x = (6-2*229^(1/2))/8

(x-((6-2*229^(1/2))/8))*(x-((2*229^(1/2)+6)/8)) = 0

((x-((6-2*229^(1/2))/8))*(x-((2*229^(1/2)+6)/8)))/(2*5) = 0

((x-((6-2*229^(1/2))/8))*(x-((2*229^(1/2)+6)/8)))/(2*5) = 0 // * 2*5

(x-((6-2*229^(1/2))/8))*(x-((2*229^(1/2)+6)/8)) = 0

( x-((2*229^(1/2)+6)/8) )

x-((2*229^(1/2)+6)/8) = 0 // + (2*229^(1/2)+6)/8

x = (2*229^(1/2)+6)/8

( x-((6-2*229^(1/2))/8) )

x-((6-2*229^(1/2))/8) = 0 // + (6-2*229^(1/2))/8

x = (6-2*229^(1/2))/8

x in { (2*229^(1/2)+6)/8, (6-2*229^(1/2))/8 }

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