(2x-3)/6-(5-4x)/4=(16x-21)/12

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Solution for (2x-3)/6-(5-4x)/4=(16x-21)/12 equation: 


x in (-oo:+oo)

(2*x-3)/6-((5-(4*x))/4) = (16*x-21)/12 // - (16*x-21)/12

(2*x-3)/6-((5-(4*x))/4)-((16*x-21)/12) = 0

(2*x-3)/6-((5-4*x)/4)-((16*x-21)/12) = 0

(2*x-3)/6+(-1*(5-4*x))/4+(-1*(16*x-21))/12 = 0

(4*12*(2*x-3))/(4*6*12)+(-1*6*12*(5-4*x))/(4*6*12)+(-1*4*6*(16*x-21))/(4*6*12) = 0

4*12*(2*x-3)-1*6*12*(5-4*x)-1*4*6*(16*x-21) = 0

384*x-384*x-504+504 = 0

0 = 0

0/(4*6*12) = 0

0/(4*6*12) = 0 // * 4*6*12

0 = 0

x belongs to the empty set

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