(2x-3)/6=2x/3+1/2

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Solution for (2x-3)/6=2x/3+1/2 equation: 


x in (-oo:+oo)

(2*x-3)/6 = (2*x)/3+1/2 // - (2*x)/3+1/2

(2*x-3)/6-((2*x)/3)-(1/2) = 0

(2*x-3)/6+(-2/3)*x-1/2 = 0

(2*x-3)/6+(-2*x)/3-1/2 = 0

(2*3*(2*x-3))/(2*3*6)+(-2*2*6*x)/(2*3*6)+(-1*3*6)/(2*3*6) = 0

2*3*(2*x-3)-2*2*6*x-1*3*6 = 0

-12*x-18-18 = 0

-12*x-36 = 0

(-12*x-36)/(2*3*6) = 0

(-12*x-36)/(2*3*6) = 0 // * 2*3*6

-12*x-36 = 0

-12*x-36 = 0 // + 36

-12*x = 36 // : -12

x = 36/(-12)

x = -3

x = -3

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