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(2x-3)/7+x=5
We move all terms to the left:
(2x-3)/7+x-(5)=0
We add all the numbers together, and all the variables
x+(2x-3)/7-5=0
We multiply all the terms by the denominator
x*7+(2x-3)-5*7=0
We add all the numbers together, and all the variables
x*7+(2x-3)-35=0
Wy multiply elements
7x+(2x-3)-35=0
We get rid of parentheses
7x+2x-3-35=0
We add all the numbers together, and all the variables
9x-38=0
We move all terms containing x to the left, all other terms to the right
9x=38
x=38/9
x=4+2/9
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