(2x-3)/7=(4x-2)/3

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Solution for (2x-3)/7=(4x-2)/3 equation:


x in (-oo:+oo)

(2*x-3)/7 = (4*x-2)/3 // - (4*x-2)/3

(2*x-3)/7-((4*x-2)/3) = 0

(2*x-3)/7+(-1*(4*x-2))/3 = 0

(3*(2*x-3))/(3*7)+(-1*7*(4*x-2))/(3*7) = 0

3*(2*x-3)-1*7*(4*x-2) = 0

5-22*x = 0

(5-22*x)/(3*7) = 0

(5-22*x)/(3*7) = 0 // * 3*7

5-22*x = 0

5-22*x = 0 // - 5

-22*x = -5 // : -22

x = -5/(-22)

x = 5/22

x = 5/22

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