(2x-3)/7=(x-1)/3

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Solution for (2x-3)/7=(x-1)/3 equation: 



(2x-3)/7=(x-1)/3

We move all terms to the left:

(2x-3)/7-((x-1)/3)=0

We calculate fractions


2x/()+(-((x-1)*7)/()=0



We calculate terms in parentheses: +(-((x-1)*7)/(), so:

-((x-1)*7)/(

We multiply all the terms by the denominator


-((x-1)*7)



We calculate terms in parentheses: -((x-1)*7), so:

(x-1)*7

We multiply parentheses

7x-7

Back to the equation:

-(7x-7)



We get rid of parentheses

-7x+7

Back to the equation:

+(-7x+7)



We get rid of parentheses

2x/()-7x+7=0

We multiply all the terms by the denominator


2x-7x*()+7*()=0

We add all the numbers together, and all the variables

2x-7x*()=0

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