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(2x-3)/7=(x-1)/3
We move all terms to the left:
(2x-3)/7-((x-1)/3)=0
We calculate fractions
2x/()+(-((x-1)*7)/()=0
We calculate terms in parentheses: +(-((x-1)*7)/(), so:We get rid of parentheses
-((x-1)*7)/(
We multiply all the terms by the denominator
-((x-1)*7)
We calculate terms in parentheses: -((x-1)*7), so:We get rid of parentheses
(x-1)*7
We multiply parentheses
7x-7
Back to the equation:
-(7x-7)
-7x+7
Back to the equation:
+(-7x+7)
2x/()-7x+7=0
We multiply all the terms by the denominator
2x-7x*()+7*()=0
We add all the numbers together, and all the variables
2x-7x*()=0
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