(2x-3)/7=37/7-2x

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Solution for (2x-3)/7=37/7-2x equation: 



(2x-3)/7=37/7-2x

We move all terms to the left:

(2x-3)/7-(37/7-2x)=0



Domain of the equation: 7-2x)!=0

We move all terms containing x to the left, all other terms to the right

-2x)!=-7

x!=-7/1

x!=-7

x∈R



We add all the numbers together, and all the variables

(2x-3)/7-(-2x+37/7)=0

We get rid of parentheses

(2x-3)/7+2x-37/7=0

We multiply all the terms by the denominator


(2x-3)+2x*7-37=0

Wy multiply elements

(2x-3)+14x-37=0

We get rid of parentheses

2x+14x-3-37=0

We add all the numbers together, and all the variables

16x-40=0

We move all terms containing x to the left, all other terms to the right

16x=40

x=40/16

x=2+1/2

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