(2x-3)2=2x+3)2+48

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Solution for (2x-3)2=2x+3)2+48 equation: 



(2x-3)2=2x+3)2+48

We move all terms to the left:

(2x-3)2-(2x+3)2+48)=0

We add all the numbers together, and all the variables

(2x-3)2-(2x+3)2=0

We multiply parentheses

4x-4x-6-6=0

We add all the numbers together, and all the variables

-12!=0

There is no solution for this equation

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