(2x-3)2=3x2-

Solution for (2x-3)2=3x2- equation:

(2x-3)2=3x^2-

We move all terms to the left:

(2x-3)2-(3x^2-)=0

We multiply parentheses

4x-(3x^2-)-6=0

We get rid of parentheses

-3x^2+4x-6+=0

We add all the numbers together, and all the variables

-3x^2+4x=0

a = -3; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-3)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-3}=\frac{-8}{-6}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-3}=\frac{0}{-6}
=0
$