(2x-3)5x+2)=0

Solution for (2x-3)5x+2)=0 equation:

(2x-3)5x+2)=0

We add all the numbers together, and all the variables

(2x-3)5x=0

We multiply parentheses

10x^2-15x=0

a = 10; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·10·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*10}=\frac{0}{20}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*10}=\frac{30}{20}
=1+1/2
$