(2x-3)7-(x-2)6-(5x+6)2=26-(3x-4)4+(6x-5)3

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Solution for (2x-3)7-(x-2)6-(5x+6)2=26-(3x-4)4+(6x-5)3 equation: 



(2x-3)7-(x-2)6-(5x+6)2=26-(3x-4)4+(6x-5)3

We move all terms to the left:

(2x-3)7-(x-2)6-(5x+6)2-(26-(3x-4)4+(6x-5)3)=0

We multiply parentheses

14x-6x-10x-(26-(3x-4)4+(6x-5)3)-21+12-12=0



We calculate terms in parentheses: -(26-(3x-4)4+(6x-5)3), so:

26-(3x-4)4+(6x-5)3

determiningTheFunctionDomain
-(3x-4)4+(6x-5)3+26

We multiply parentheses

-12x+18x+16-15+26

We add all the numbers together, and all the variables

6x+27

Back to the equation:

-(6x+27)



We add all the numbers together, and all the variables

-2x-(6x+27)-21=0

We get rid of parentheses

-2x-6x-27-21=0

We add all the numbers together, and all the variables

-8x-48=0

We move all terms containing x to the left, all other terms to the right

-8x=48

x=48/-8

x=-6

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