(2x-3)=(3x-2)+90

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Solution for (2x-3)=(3x-2)+90 equation: 



(2x-3)=(3x-2)+90

We move all terms to the left:

(2x-3)-((3x-2)+90)=0

We get rid of parentheses

2x-((3x-2)+90)-3=0



We calculate terms in parentheses: -((3x-2)+90), so:

(3x-2)+90

We get rid of parentheses

3x-2+90

We add all the numbers together, and all the variables

3x+88

Back to the equation:

-(3x+88)



We get rid of parentheses

2x-3x-88-3=0

We add all the numbers together, and all the variables

-1x-91=0

We move all terms containing x to the left, all other terms to the right

-x=91

x=91/-1

x=-91

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