(2x-3)=(3x-2)-90

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Solution for (2x-3)=(3x-2)-90 equation: 



(2x-3)=(3x-2)-90

We move all terms to the left:

(2x-3)-((3x-2)-90)=0

We get rid of parentheses

2x-((3x-2)-90)-3=0



We calculate terms in parentheses: -((3x-2)-90), so:

(3x-2)-90

We get rid of parentheses

3x-2-90

We add all the numbers together, and all the variables

3x-92

Back to the equation:

-(3x-92)



We get rid of parentheses

2x-3x+92-3=0

We add all the numbers together, and all the variables

-1x+89=0

We move all terms containing x to the left, all other terms to the right

-x=-89

x=-89/-1

x=+89

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