(2x-3)=(3x-2)=90

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Solution for (2x-3)=(3x-2)=90 equation: 



(2x-3)=(3x-2)=90

We move all terms to the left:

(2x-3)-((3x-2))=0

We get rid of parentheses

2x-((3x-2))-3=0



We calculate terms in parentheses: -((3x-2)), so:

(3x-2)

We get rid of parentheses

3x-2

Back to the equation:

-(3x-2)



We get rid of parentheses

2x-3x+2-3=0

We add all the numbers together, and all the variables

-1x-1=0

We move all terms containing x to the left, all other terms to the right

-x=1

x=1/-1

x=-1

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