(2x-3)=3(5x-12)/10

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Solution for (2x-3)=3(5x-12)/10 equation: 



(2x-3)=3(5x-12)/10

We move all terms to the left:

(2x-3)-(3(5x-12)/10)=0

We get rid of parentheses

2x-(3(5x-12)/10)-3=0

We multiply all the terms by the denominator


2x*10)-(3(5x-12)-3*10)=0

We add all the numbers together, and all the variables

2x*10)-(3(5x-12)=0

Wy multiply elements

20x^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{40}=0$

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