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(2x-3)x=56-5
We move all terms to the left:
(2x-3)x-(56-5)=0
We add all the numbers together, and all the variables
(2x-3)x-51=0
We multiply parentheses
2x^2-3x-51=0
a = 2; b = -3; c = -51;
Δ = b2-4ac
Δ = -32-4·2·(-51)
Δ = 417
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{417}}{2*2}=\frac{3-\sqrt{417}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{417}}{2*2}=\frac{3+\sqrt{417}}{4} $
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