(2x-3/1-x)-1=(4x+4/1-x)+x

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Solution for (2x-3/1-x)-1=(4x+4/1-x)+x equation: 



(2x-3/1-x)-1=(4x+4/1-x)+x

We move all terms to the left:

(2x-3/1-x)-1-((4x+4/1-x)+x)=0



Domain of the equation: 1-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-1

x!=-1/1

x!=-1

x∈R





Domain of the equation: 1-x)+x)!=0

We move all terms containing x to the left, all other terms to the right

-x)+x)!=-1

x!=-1/1

x!=-1

x∈R



We add all the numbers together, and all the variables

(x-3)-((+3x)+x)-1=0

We get rid of parentheses

x-((+3x)+x)-3-1=0



We calculate terms in parentheses: -((+3x)+x), so:

(+3x)+x

We add all the numbers together, and all the variables

x+(+3x)

We get rid of parentheses

x+3x

We add all the numbers together, and all the variables

4x

Back to the equation:

-(4x)



We add all the numbers together, and all the variables

-3x-4=0

We move all terms containing x to the left, all other terms to the right

-3x=4

x=4/-3

x=-1+1/3

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