(2x-3/x-1)=(8x+1/4x+5)

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Solution for (2x-3/x-1)=(8x+1/4x+5) equation: 



(2x-3/x-1)=(8x+1/4x+5)

We move all terms to the left:

(2x-3/x-1)-((8x+1/4x+5))=0



Domain of the equation: x-1)!=0

x∈R





Domain of the equation: 4x+5))!=0

x∈R



We get rid of parentheses

2x-3/x-((8x+1/4x+5))-1=0

We calculate fractions


2x+(-12x)/4x^2+(-((8x+1*x)/4x^2-1=0

We add all the numbers together, and all the variables

2x+(-12x)/4x^2+(-((+9x)/4x^2-1=0

We calculate fractions

We do not support expression: x^4

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